The National Testing Agency on Friday announced the final results of the controversy-ridden medical entrance exam NEET-UG. The results were declared following directive from the Supreme Court after taking into account marks of a physics question, which the NTA had said has two correct answers.
NEET UG Final Scorecard Out: Number Of Toppers Drops From 61 To 17 | Direct Link Here
The results were declared following directive from the Supreme Court after taking into account marks of a physics question, which the NTA had said has two correct answers.
The top court, on Tuesday, had directed the NTA to re-evaluate the scores in light of the expert opinion from IIT Delhi concerning a physics question, saying that two options cannot be treated as the correct answers to a question.
“We accept the IIT Delhi report and accordingly NTA shall re-tally the NEET UG result on the basis that option 4 represents the only correct answer to the question,” Chief Justice of India (CJI) DY Chandrachud had stated.
A total of 17 candidates are now tied for the top rank, down from 61 in the previous revised results. Forty-four out of the 67 candidates who were earlier declared toppers had scored full marks because of the marks awarded for that particular physics question. The number of toppers was later reduced to 61 with the agency withdrawing grace marks awarded to six candidates to make up for loss of time at few exam centres.
In a major setback to unsuccessful aspirants of NEET-UG 2024, the Supreme Court on Tuesday dismissed the pleas seeking cancellation and re-test of the controversy-ridden exam, holding that there was no evidence on record to conclude that it was "vitiated" on account of "systemic breach" of its sanctity.
The CBI is probing alleged irregularities in NEET-UG 2024 and has lodged six FIRs.
NEET UG Revised Results 2024: Where To Check?
The candidates who have appeared for the NEET-UG exams can check their scorecard on the official website - exams.nta.ac.in/NEET.
The alternative website to check the results - neet.ntaonline.in.